Given an absolute path for a file (Unix-style), simplify it.

For example,

path = "/home/", => "/home"

path = "/a/./b/../../c/", => "/c"

Corner Cases:

 

• Did you consider the case where path = "/../"?
  In this case, you should return "/".
• Another corner case is the path might contain multiple slashes '/' together, such as "/home//foo/".
  In this case, you should ignore redundant slashes and return "/home/foo".

 

Runtime: 6ms

1 class Solution { 2 public: 3     string simplifyPath(string path) { 4         string newPath; 5         vector
      
        directory; 6         stringstream newString(path); 7         string temp; 8         while (getline(newString, temp, '/')) { 9             if (temp == "." || temp == "") continue;10             else if (temp == ".." && !directory.empty()) directory.pop_back();11             else if (temp != "..") directory.push_back(temp);12         }13         14         for (string current : directory) {15             newPath += "/" + current;16         }17         return newPath.empty() ? "/" : newPath;18     }19 };